What is the molality of a solution containing 3 moles of solute in 500 g of solv

Practice Questions

Q1
What is the molality of a solution containing 3 moles of solute in 500 g of solvent? (2021)
  1. 6 m
  2. 3 m
  3. 1.5 m
  4. 0.5 m

Questions & Step-by-Step Solutions

What is the molality of a solution containing 3 moles of solute in 500 g of solvent? (2021)
  • Step 1: Identify the number of moles of solute. In this case, there are 3 moles of solute.
  • Step 2: Identify the mass of the solvent. Here, the mass of the solvent is 500 grams.
  • Step 3: Convert the mass of the solvent from grams to kilograms. Since 1000 grams = 1 kilogram, 500 grams is equal to 0.5 kilograms.
  • Step 4: Use the formula for molality, which is molality (m) = moles of solute / kg of solvent.
  • Step 5: Plug in the values into the formula: m = 3 moles / 0.5 kg.
  • Step 6: Calculate the result: 3 divided by 0.5 equals 6.
  • Step 7: Therefore, the molality of the solution is 6 m.
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