Find the x-coordinate of the point where the function f(x) = x^2 - 4x + 5 has a

Practice Questions

Q1
Find the x-coordinate of the point where the function f(x) = x^2 - 4x + 5 has a minimum.
  1. 2
  2. 1
  3. 3
  4. 0

Questions & Step-by-Step Solutions

Find the x-coordinate of the point where the function f(x) = x^2 - 4x + 5 has a minimum.
Correct Answer: 2
  • Step 1: Identify the function you are working with, which is f(x) = x^2 - 4x + 5.
  • Step 2: Recognize that this is a quadratic function in the form of ax^2 + bx + c, where a = 1, b = -4, and c = 5.
  • Step 3: To find the x-coordinate of the minimum point, use the formula x = -b/(2a).
  • Step 4: Substitute the values of a and b into the formula: x = -(-4)/(2*1).
  • Step 5: Simplify the expression: x = 4/2.
  • Step 6: Calculate the result: x = 2.
  • Step 7: Conclude that the x-coordinate of the point where the function has a minimum is 2.
  • Quadratic Functions – Understanding the properties of quadratic functions, including how to find the vertex and minimum value.
  • Vertex Formula – Using the vertex formula x = -b/(2a) to find the x-coordinate of the vertex of a parabola.
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