A 1 kg ball is thrown horizontally from a height of 5 m. How long does it take t

A 1 kg ball is thrown horizontally from a height of 5 m. How long does it take to hit the ground? (g = 10 m/s²) (2022)

A 1 kg ball is thrown horizontally from a height of 5 m. How long does it take to hit the ground? (g = 10 m/s²) (2022)

Step 1: Identify the height from which the ball is thrown. In this case, the height (h) is 5 meters.
Step 2: Use the formula for free fall: h = 1/2 * g * t², where g is the acceleration due to gravity (10 m/s²) and t is the time in seconds.
Step 3: Substitute the known values into the formula: 5 m = 1/2 * 10 m/s² * t².
Step 4: Simplify the equation: 5 m = 5 m/s² * t².
Step 5: Divide both sides by 5 m/s² to isolate t²: t² = 1 s².
Step 6: Take the square root of both sides to find t: t = √1 = 1 s.

Projectile Motion – The question tests understanding of the motion of an object under the influence of gravity, specifically how vertical motion is independent of horizontal motion.
Kinematic Equations – The use of the kinematic equation h = 1/2 gt² to determine the time of fall based on the height and acceleration due to gravity.