A 15 kg box is pulled with a force of 60 N at an angle of 30° to the horizontal.

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Question: A 15 kg box is pulled with a force of 60 N at an angle of 30° to the horizontal. What is the horizontal component of the force? (2022)

Options:

Correct Answer: 51.96 N

Exam Year: 2022

Solution:

Horizontal component = F * cos(θ) = 60 N * cos(30°) = 60 N * (√3/2) = 51.96 N.

A 15 kg box is pulled with a force of 60 N at an angle of 30° to the horizontal. What is the horizontal component of the force? (2022)

A 15 kg box is pulled with a force of 60 N at an angle of 30° to the horizontal. What is the horizontal component of the force? (2022)

Step 1: Identify the total force being applied, which is 60 N.
Step 2: Identify the angle at which the force is applied, which is 30°.
Step 3: Use the formula to find the horizontal component of the force: Horizontal component = F * cos(θ).
Step 4: Substitute the values into the formula: Horizontal component = 60 N * cos(30°).
Step 5: Calculate cos(30°), which is √3/2 or approximately 0.866.
Step 6: Multiply 60 N by cos(30°): Horizontal component = 60 N * (√3/2).
Step 7: Calculate the result: 60 N * (√3/2) = 60 N * 0.866 = 51.96 N.

Force Components – Understanding how to resolve a force into its horizontal and vertical components using trigonometric functions.
Trigonometry in Physics – Applying cosine to find the horizontal component of a force when given an angle.