My Learning Cart
?
Categories
Account

A 5 kg block of ice at 0°C is placed in a calorimeter containing 2 kg of water a

₹0.0
Login to Download
  • 📥 Instant PDF Download
  • ♾ Lifetime Access
  • 🛡 Secure & Original Content

What’s inside this PDF?

Question: A 5 kg block of ice at 0°C is placed in a calorimeter containing 2 kg of water at 80°C. What is the final temperature of the system when thermal equilibrium is reached? (Latent heat of fusion of ice = 334 kJ/kg)

Options:

  1. 0°C
  2. 20°C
  3. 40°C
  4. 60°C

Correct Answer: 20°C

Solution: 

The heat lost by water = heat gained by ice. Solving gives the final temperature as 0°C.

A 5 kg block of ice at 0°C is placed in a calorimeter containing 2 kg of water a

Practice Questions

Q1
A 5 kg block of ice at 0°C is placed in a calorimeter containing 2 kg of water at 80°C. What is the final temperature of the system when thermal equilibrium is reached? (Latent heat of fusion of ice = 334 kJ/kg)
  1. 0°C
  2. 20°C
  3. 40°C
  4. 60°C

Questions & Step-by-Step Solutions

A 5 kg block of ice at 0°C is placed in a calorimeter containing 2 kg of water at 80°C. What is the final temperature of the system when thermal equilibrium is reached? (Latent heat of fusion of ice = 334 kJ/kg)
Correct Answer: 0°C
  • Step 1: Identify the mass of the ice block, which is 5 kg, and its initial temperature, which is 0°C.
  • Step 2: Identify the mass of the water, which is 2 kg, and its initial temperature, which is 80°C.
  • Step 3: Understand that when the ice is placed in the water, the water will lose heat and the ice will gain heat until they reach the same final temperature.
  • Step 4: Calculate the heat required to melt the ice using the formula: Heat = mass of ice × latent heat of fusion. Here, it is 5 kg × 334 kJ/kg = 1670 kJ.
  • Step 5: Calculate the heat lost by the water as it cools down. The water will cool down to the final temperature (Tf). The formula for heat lost is: Heat = mass of water × specific heat of water × change in temperature. The specific heat of water is approximately 4.18 kJ/kg°C.
  • Step 6: Set up the equation: Heat lost by water = Heat gained by ice. This means: (2 kg × 4.18 kJ/kg°C × (80°C - Tf)) = 1670 kJ.
  • Step 7: Solve the equation for Tf. After calculations, you will find that Tf equals 0°C.
  • Step 8: Conclude that the final temperature of the system when thermal equilibrium is reached is 0°C.
  • Heat Transfer – Understanding how heat is exchanged between substances at different temperatures until thermal equilibrium is reached.
  • Latent Heat of Fusion – The energy required to change a substance from solid to liquid at its melting point without changing its temperature.
  • Thermal Equilibrium – The state in which two or more bodies in thermal contact no longer exchange heat, resulting in a uniform temperature.
Soulshift Feedback ×

On a scale of 0–10, how likely are you to recommend The Soulshift Academy?

Not likely Very likely
Home Practice Performance eBooks