For the function f(x) = x^2 - 4x + 5, find the vertex.

Practice Questions

Q1
For the function f(x) = x^2 - 4x + 5, find the vertex.
  1. (2, 1)
  2. (2, 5)
  3. (4, 1)
  4. (4, 5)

Questions & Step-by-Step Solutions

For the function f(x) = x^2 - 4x + 5, find the vertex.
Correct Answer: (2, 1)
  • Step 1: Identify the coefficients a, b, and c from the function f(x) = x^2 - 4x + 5. Here, a = 1, b = -4, and c = 5.
  • Step 2: Use the formula for the x-coordinate of the vertex, which is x = -b/(2a). Substitute the values of b and a: x = -(-4)/(2*1).
  • Step 3: Simplify the expression: x = 4/2 = 2. This gives us the x-coordinate of the vertex.
  • Step 4: Now, find the y-coordinate of the vertex by substituting x = 2 back into the function f(x). Calculate f(2) = 2^2 - 4(2) + 5.
  • Step 5: Simplify f(2): f(2) = 4 - 8 + 5 = 1. This gives us the y-coordinate of the vertex.
  • Step 6: Combine the x and y coordinates to find the vertex. The vertex is (2, 1).
  • Quadratic Functions – Understanding the standard form of a quadratic function and how to find its vertex using the formula x = -b/(2a).
  • Vertex Calculation – Calculating the vertex of a parabola given in the form f(x) = ax^2 + bx + c.
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