If f(x) = x^3 - 6x^2 + 9x, find the critical points.

Practice Questions

Q1
If f(x) = x^3 - 6x^2 + 9x, find the critical points.
  1. (0, 0)
  2. (3, 0)
  3. (2, 0)
  4. (1, 0)

Questions & Step-by-Step Solutions

If f(x) = x^3 - 6x^2 + 9x, find the critical points.
Correct Answer: x = 1 and x = 3
  • Step 1: Start with the function f(x) = x^3 - 6x^2 + 9x.
  • Step 2: Find the derivative of the function, which is f'(x). The derivative tells us the rate of change of the function.
  • Step 3: Calculate the derivative: f'(x) = 3x^2 - 12x + 9.
  • Step 4: Set the derivative equal to zero to find critical points: 3x^2 - 12x + 9 = 0.
  • Step 5: Factor the equation: (x - 3)(x - 1) = 0.
  • Step 6: Solve for x by setting each factor equal to zero: x - 3 = 0 gives x = 3, and x - 1 = 0 gives x = 1.
  • Step 7: The critical points are x = 1 and x = 3.
  • Finding Critical Points – This involves taking the derivative of a function and setting it to zero to find points where the function's slope is zero, indicating potential local maxima, minima, or points of inflection.
  • Derivative Calculation – Understanding how to correctly differentiate polynomial functions is crucial for finding critical points.
  • Factoring Quadratics – The ability to factor quadratic equations is necessary to solve for the roots of the derivative.
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