For the function f(x) = -x^2 + 6x, find the x-coordinate of the vertex. (2022)

Practice Questions

Q1
For the function f(x) = -x^2 + 6x, find the x-coordinate of the vertex. (2022)
  1. 3
  2. 2
  3. 4
  4. 1

Questions & Step-by-Step Solutions

For the function f(x) = -x^2 + 6x, find the x-coordinate of the vertex. (2022)
  • Step 1: Identify the coefficients a and b from the function f(x) = -x^2 + 6x. Here, a = -1 and b = 6.
  • Step 2: Use the formula for the x-coordinate of the vertex, which is x = -b/(2a).
  • Step 3: Substitute the values of b and a into the formula: x = -6/(2 * -1).
  • Step 4: Calculate the denominator: 2 * -1 = -2.
  • Step 5: Now, substitute this value back into the equation: x = -6 / -2.
  • Step 6: Simplify the fraction: -6 divided by -2 equals 3.
  • Step 7: Therefore, the x-coordinate of the vertex is 3.
  • Quadratic Functions – Understanding the standard form of a quadratic function and how to find the vertex using the formula x = -b/(2a).
  • Vertex of a Parabola – Identifying the vertex of a parabola represented by a quadratic function and its significance in graphing.
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