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In a series circuit with a 12V battery and two resistors of 4Ω and 8Ω, what is the voltage across the 8Ω resistor? (2022)

Practice Questions

1 question
Q1
In a series circuit with a 12V battery and two resistors of 4Ω and 8Ω, what is the voltage across the 8Ω resistor? (2022)
  1. 4V
  2. 6V
  3. 8V
  4. 12V

Questions & Step-by-step Solutions

1 item
Q
Q: In a series circuit with a 12V battery and two resistors of 4Ω and 8Ω, what is the voltage across the 8Ω resistor? (2022)
Solution: Total resistance R_total = 4Ω + 8Ω = 12Ω. Current I = V/R_total = 12V/12Ω = 1A. Voltage across 8Ω = I * R = 1A * 8Ω = 8V.
Steps: 0

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