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For the quadratic equation x^2 + 6x + 8 = 0, what are the roots?
For the quadratic equation x^2 + 6x + 8 = 0, what are the roots?
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Practice Questions
1 question
Q1
For the quadratic equation x^2 + 6x + 8 = 0, what are the roots?
-2 and -4
-4 and -2
2 and 4
0 and 8
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Factoring gives (x+2)(x+4) = 0, hence the roots are -2 and -4.
Questions & Step-by-step Solutions
1 item
Q
Q: For the quadratic equation x^2 + 6x + 8 = 0, what are the roots?
Solution:
Factoring gives (x+2)(x+4) = 0, hence the roots are -2 and -4.
Steps: 7
Show Steps
Step 1: Start with the quadratic equation x^2 + 6x + 8 = 0.
Step 2: Look for two numbers that multiply to 8 (the constant term) and add up to 6 (the coefficient of x).
Step 3: The numbers 2 and 4 work because 2 * 4 = 8 and 2 + 4 = 6.
Step 4: Rewrite the equation using these numbers: (x + 2)(x + 4) = 0.
Step 5: Set each factor equal to zero: x + 2 = 0 and x + 4 = 0.
Step 6: Solve for x in each equation: x = -2 and x = -4.
Step 7: The roots of the equation are -2 and -4.
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