If 10 g of sugar (C12H22O11) is dissolved in 200 g of water, what is the mass percent of the solution? (2023)
Practice Questions
1 question
Q1
If 10 g of sugar (C12H22O11) is dissolved in 200 g of water, what is the mass percent of the solution? (2023)
4.76%
5.00%
10.00%
20.00%
Mass percent = (mass of solute / mass of solution) × 100. Mass of solution = 10 g + 200 g = 210 g. Mass percent = (10 g / 210 g) × 100 = 4.76%.
Questions & Step-by-step Solutions
1 item
Q
Q: If 10 g of sugar (C12H22O11) is dissolved in 200 g of water, what is the mass percent of the solution? (2023)
Solution: Mass percent = (mass of solute / mass of solution) × 100. Mass of solution = 10 g + 200 g = 210 g. Mass percent = (10 g / 210 g) × 100 = 4.76%.
Steps: 6
Step 1: Identify the mass of the solute (sugar) which is 10 g.
Step 2: Identify the mass of the solvent (water) which is 200 g.
Step 3: Calculate the total mass of the solution by adding the mass of the solute and the mass of the solvent: 10 g + 200 g = 210 g.
Step 4: Use the mass percent formula: Mass percent = (mass of solute / mass of solution) × 100.
Step 5: Substitute the values into the formula: Mass percent = (10 g / 210 g) × 100.
Step 6: Calculate the mass percent: 10 g / 210 g = 0.047619, then multiply by 100 to get 4.76%.
