What is the osmotic pressure of a solution containing 2 moles of glucose in 1 li

What is the osmotic pressure of a solution containing 2 moles of glucose in 1 liter of solution at 25 °C? (R = 0.0821 L·atm/(K·mol)) (2020)

What is the osmotic pressure of a solution containing 2 moles of glucose in 1 liter of solution at 25 °C? (R = 0.0821 L·atm/(K·mol)) (2020)

Step 1: Identify the formula for osmotic pressure, which is π = nRT/V.
Step 2: Determine the values needed for the formula: n (number of moles) = 2 moles, R (gas constant) = 0.0821 L·atm/(K·mol), T (temperature in Kelvin) = 25 °C + 273 = 298 K, and V (volume in liters) = 1 L.
Step 3: Plug the values into the formula: π = (2 moles * 0.0821 L·atm/(K·mol) * 298 K) / 1 L.
Step 4: Calculate the numerator: 2 * 0.0821 * 298 = 49.0524.
Step 5: Since the volume is 1 L, the osmotic pressure is simply 49.0524 atm.
Step 6: Round the answer to two decimal places: π = 4.92 atm.

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