A coil of wire has 100 turns and is placed in a magnetic field of strength 0.5 T
Practice Questions
Q1
A coil of wire has 100 turns and is placed in a magnetic field of strength 0.5 T. If the area of the coil is 0.1 m², what is the maximum magnetic flux through the coil? (2022)
5 Wb
0.5 Wb
10 Wb
1 Wb
Questions & Step-by-Step Solutions
A coil of wire has 100 turns and is placed in a magnetic field of strength 0.5 T. If the area of the coil is 0.1 m², what is the maximum magnetic flux through the coil? (2022)
Step 1: Identify the formula for magnetic flux (Φ). The formula is Φ = B × A × N, where B is the magnetic field strength, A is the area of the coil, and N is the number of turns in the coil.
Step 2: Write down the values given in the question: B = 0.5 T (Tesla), A = 0.1 m² (square meters), and N = 100 (turns).
Step 3: Substitute the values into the formula: Φ = 0.5 T × 0.1 m² × 100.
Step 4: Calculate the product: First, multiply 0.5 T by 0.1 m² to get 0.05. Then, multiply 0.05 by 100 to get 5.
Step 5: Conclude that the maximum magnetic flux through the coil is 5 Wb (Webers).
Magnetic Flux – Magnetic flux (Φ) is the product of the magnetic field strength (B), the area (A) through which the field lines pass, and the number of turns (N) in the coil.
