What is the time complexity of inserting a node in a binary search tree in the a
Practice Questions
Q1
What is the time complexity of inserting a node in a binary search tree in the average case?
O(n)
O(log n)
O(n log n)
O(1)
Questions & Step-by-Step Solutions
What is the time complexity of inserting a node in a binary search tree in the average case?
Step 1: Understand what a binary search tree (BST) is. A BST is a data structure where each node has at most two children, and the left child is less than the parent node, while the right child is greater.
Step 2: Know that when we insert a new node into a BST, we start at the root node and compare the value of the new node with the current node's value.
Step 3: If the new node's value is less than the current node's value, we move to the left child; if it's greater, we move to the right child.
Step 4: We repeat this process until we find an empty spot (null) where we can insert the new node.
Step 5: In a balanced BST, the height of the tree is log(n), where n is the number of nodes. This means that, on average, we will make log(n) comparisons to find the right spot for the new node.
Step 6: Therefore, the average case time complexity for inserting a node in a binary search tree is O(log n).
