A charge of +10 μC is placed in an electric field of 2000 N/C. What is the force
Practice Questions
Q1
A charge of +10 μC is placed in an electric field of 2000 N/C. What is the force experienced by the charge? (2023)
20 N
200 N
2 N
0.2 N
Questions & Step-by-Step Solutions
A charge of +10 μC is placed in an electric field of 2000 N/C. What is the force experienced by the charge? (2023)
Step 1: Identify the charge (q) which is +10 μC. Convert this to coulombs: +10 μC = 10 × 10^-6 C.
Step 2: Identify the electric field strength (E) which is 2000 N/C.
Step 3: Use the formula for force (F) in an electric field: F = qE.
Step 4: Substitute the values into the formula: F = (10 × 10^-6 C) * (2000 N/C).
Step 5: Calculate the force: F = 0.02 N.
Step 6: Convert 0.02 N to a more understandable form: 0.02 N = 20 mN (milliNewtons).
Coulomb's Law – The force experienced by a charge in an electric field is calculated using the formula F = qE, where F is the force, q is the charge, and E is the electric field strength.
