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In a circuit with a 12V battery and two 4Ω resistors in series, what is the curr

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Question: In a circuit with a 12V battery and two 4Ω resistors in series, what is the current flowing through the circuit? (2023)

Options:

  1. 1A
  2. 2A
  3. 3A
  4. 4A

Correct Answer: 2A

Exam Year: 2023

Solution: 

Total resistance R = 4Ω + 4Ω = 8Ω. Current I = V/R = 12V/8Ω = 1.5A.

In a circuit with a 12V battery and two 4Ω resistors in series, what is the curr

Practice Questions

Q1
In a circuit with a 12V battery and two 4Ω resistors in series, what is the current flowing through the circuit? (2023)
  1. 1A
  2. 2A
  3. 3A
  4. 4A

Questions & Step-by-Step Solutions

In a circuit with a 12V battery and two 4Ω resistors in series, what is the current flowing through the circuit? (2023)
  • Step 1: Identify the voltage of the battery, which is 12V.
  • Step 2: Identify the resistance of each resistor, which is 4Ω.
  • Step 3: Since the resistors are in series, add their resistances together: 4Ω + 4Ω = 8Ω.
  • Step 4: Use Ohm's Law to find the current. Ohm's Law states that Current (I) = Voltage (V) / Resistance (R).
  • Step 5: Substitute the values into the formula: I = 12V / 8Ω.
  • Step 6: Calculate the current: 12V divided by 8Ω equals 1.5A.
  • Ohm's Law – Ohm's Law states that the current (I) through a conductor between two points is directly proportional to the voltage (V) across the two points and inversely proportional to the resistance (R) of the conductor.
  • Series Circuits – In a series circuit, the total resistance is the sum of the individual resistances, and the same current flows through all components.
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