In a double-slit experiment, if the distance between the slits is 0.1 mm and the
Practice Questions
Q1
In a double-slit experiment, if the distance between the slits is 0.1 mm and the screen is 1 m away, what is the fringe separation for light of wavelength 500 nm? (2020)
0.5 mm
0.1 mm
0.2 mm
0.3 mm
Questions & Step-by-Step Solutions
In a double-slit experiment, if the distance between the slits is 0.1 mm and the screen is 1 m away, what is the fringe separation for light of wavelength 500 nm? (2020)
Step 1: Identify the given values from the problem. The distance between the slits (d) is 0.1 mm, the distance to the screen (D) is 1 m, and the wavelength of light (λ) is 500 nm.
Step 2: Convert all measurements to the same unit. Convert 0.1 mm to meters: 0.1 mm = 0.1 x 10^-3 m. Convert 500 nm to meters: 500 nm = 500 x 10^-9 m.
Step 3: Use the formula for fringe separation (β): β = λD/d.
Step 4: Substitute the values into the formula: β = (500 x 10^-9 m)(1 m) / (0.1 x 10^-3 m).
Step 5: Calculate the numerator: 500 x 10^-9 m * 1 m = 500 x 10^-9 m.
Step 6: Calculate the denominator: 0.1 x 10^-3 m = 0.1 x 10^-3 m.
Step 7: Divide the numerator by the denominator: β = (500 x 10^-9 m) / (0.1 x 10^-3 m).
Step 8: Perform the division: β = 5000 x 10^-6 m = 0.5 mm.
