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In an AC circuit, if the voltage is given by V(t) = V₀ sin(ωt), what is the expr

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Question: In an AC circuit, if the voltage is given by V(t) = V₀ sin(ωt), what is the expression for the current through a capacitor? (2022)

Options:

  1. I(t) = C dV/dt
  2. I(t) = V₀ sin(ωt)
  3. I(t) = V₀ cos(ωt)
  4. I(t) = V₀ sin(ωt)/R

Correct Answer: I(t) = C dV/dt

Exam Year: 2022

Solution:

The current through a capacitor is given by I(t) = C dV/dt. For V(t) = V₀ sin(ωt), the current can be derived from this expression.

In an AC circuit, if the voltage is given by V(t) = V₀ sin(ωt), what is the expr

Practice Questions

Q1
In an AC circuit, if the voltage is given by V(t) = V₀ sin(ωt), what is the expression for the current through a capacitor? (2022)
  1. I(t) = C dV/dt
  2. I(t) = V₀ sin(ωt)
  3. I(t) = V₀ cos(ωt)
  4. I(t) = V₀ sin(ωt)/R

Questions & Step-by-Step Solutions

In an AC circuit, if the voltage is given by V(t) = V₀ sin(ωt), what is the expression for the current through a capacitor? (2022)
  • Step 1: Identify the voltage function given in the problem, which is V(t) = V₀ sin(ωt).
  • Step 2: Recall the formula for current through a capacitor, which is I(t) = C dV/dt.
  • Step 3: Differentiate the voltage function V(t) with respect to time t to find dV/dt.
  • Step 4: Calculate dV/dt: dV/dt = d/dt [V₀ sin(ωt)] = V₀ ω cos(ωt).
  • Step 5: Substitute dV/dt back into the current formula: I(t) = C (V₀ ω cos(ωt)).
  • Step 6: Simplify the expression to get the final result: I(t) = C V₀ ω cos(ωt).
  • Capacitor Current Relationship – The relationship between voltage and current in a capacitor, where current is the derivative of voltage with respect to time multiplied by capacitance.
  • AC Circuit Analysis – Understanding how alternating current (AC) behaves in circuits, particularly with reactive components like capacitors.
  • Differentiation in AC Functions – Applying calculus to find the rate of change of sinusoidal functions, which is essential for determining current from voltage.
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