What is the main product of the reaction of 1-bromo-2-methylpropane with KOH in
Practice Questions
Q1
What is the main product of the reaction of 1-bromo-2-methylpropane with KOH in ethanol? (2020)
2-methylpropene
2-methylpropan-1-ol
1-bromo-2-methylpropane
2-bromo-2-methylpropane
Questions & Step-by-Step Solutions
What is the main product of the reaction of 1-bromo-2-methylpropane with KOH in ethanol? (2020)
Step 1: Identify the starting material, which is 1-bromo-2-methylpropane. This is a molecule with a bromine atom attached to a carbon chain.
Step 2: Recognize that KOH (potassium hydroxide) is a strong base that can promote elimination reactions.
Step 3: Understand that in the presence of KOH and ethanol, the bromine atom can be removed from 1-bromo-2-methylpropane.
Step 4: Realize that when the bromine is removed, a double bond forms between the carbon atoms, resulting in the formation of an alkene.
Step 5: Determine the structure of the product. The double bond will form between the second and third carbon atoms, leading to the product 2-methylpropene.
