What is the main product of the reaction of 1-bromo-2-methylpropane with KOH in

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Question: What is the main product of the reaction of 1-bromo-2-methylpropane with KOH in ethanol? (2020)

Options:

Correct Answer: 2-methylpropene

Exam Year: 2020

Solution:

The reaction of 1-bromo-2-methylpropane with KOH in ethanol leads to the formation of 2-methylpropene through an elimination reaction.

What is the main product of the reaction of 1-bromo-2-methylpropane with KOH in ethanol? (2020)

What is the main product of the reaction of 1-bromo-2-methylpropane with KOH in ethanol? (2020)

Step 1: Identify the starting material, which is 1-bromo-2-methylpropane. This is a molecule with a bromine atom attached to a carbon chain.
Step 2: Recognize that KOH (potassium hydroxide) is a strong base that can promote elimination reactions.
Step 3: Understand that in the presence of KOH and ethanol, the bromine atom can be removed from 1-bromo-2-methylpropane.
Step 4: Realize that when the bromine is removed, a double bond forms between the carbon atoms, resulting in the formation of an alkene.
Step 5: Determine the structure of the product. The double bond will form between the second and third carbon atoms, leading to the product 2-methylpropene.

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