A metal rod is heated at one end. If the temperature at the heated end is 100°C

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Question: A metal rod is heated at one end. If the temperature at the heated end is 100°C and the other end is at 20°C, what is the temperature gradient along the rod?

Options:

80°C/m
20°C/m
10°C/m
5°C/m

Correct Answer: 10°C/m

Solution:

Temperature gradient = (T_hot - T_cold) / Length. Assuming length is 8 m, gradient = (100°C - 20°C) / 8 m = 10°C/m.

A metal rod is heated at one end. If the temperature at the heated end is 100°C

Practice Questions

A metal rod is heated at one end. If the temperature at the heated end is 100°C and the other end is at 20°C, what is the temperature gradient along the rod?

80°C/m
20°C/m
10°C/m
5°C/m

Questions & Step-by-Step Solutions

A metal rod is heated at one end. If the temperature at the heated end is 100°C and the other end is at 20°C, what is the temperature gradient along the rod?

Step 1: Identify the temperature at the hot end of the rod, which is 100°C.
Step 2: Identify the temperature at the cold end of the rod, which is 20°C.
Step 3: Calculate the difference in temperature by subtracting the cold end temperature from the hot end temperature: 100°C - 20°C.
Step 4: Assume the length of the rod is 8 meters.
Step 5: Use the formula for temperature gradient: (T_hot - T_cold) / Length.
Step 6: Substitute the values into the formula: (100°C - 20°C) / 8 m.
Step 7: Calculate the difference in temperature: 100°C - 20°C = 80°C.
Step 8: Divide the temperature difference by the length of the rod: 80°C / 8 m = 10°C/m.
Step 9: Conclude that the temperature gradient along the rod is 10°C/m.

Temperature Gradient – The temperature gradient is the rate of temperature change per unit length, calculated by the difference in temperature between two points divided by the distance between them.

A metal rod is heated at one end. If the temperature at the heated end is 100°C

What’s inside this PDF?

A metal rod is heated at one end. If the temperature at the heated end is 100°C

Practice Questions

Questions & Step-by-Step Solutions

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