If 200 J of heat is added to a system and 50 J of work is done by the system, wh

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Question: If 200 J of heat is added to a system and 50 J of work is done by the system, what is the change in internal energy of the system?

Options:

Correct Answer: 150 J

Solution:

According to the first law of thermodynamics, ΔU = Q - W = 200 J - 50 J = 150 J.

If 200 J of heat is added to a system and 50 J of work is done by the system, what is the change in internal energy of the system?

If 200 J of heat is added to a system and 50 J of work is done by the system, what is the change in internal energy of the system?

Step 1: Identify the amount of heat added to the system, which is 200 J. This is represented as Q.
Step 2: Identify the amount of work done by the system, which is 50 J. This is represented as W.
Step 3: Use the formula from the first law of thermodynamics, which states that the change in internal energy (ΔU) is equal to the heat added (Q) minus the work done (W).
Step 4: Substitute the values into the formula: ΔU = Q - W = 200 J - 50 J.
Step 5: Calculate the result: 200 J - 50 J = 150 J.
Step 6: Conclude that the change in internal energy of the system is 150 J.

First Law of Thermodynamics – The principle that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system.