A spring is compressed by 0.1 m and has a spring constant of 200 N/m. What is th

₹0.0

Question: A spring is compressed by 0.1 m and has a spring constant of 200 N/m. What is the potential energy stored in the spring? (2019)

Options:

Correct Answer: 1 J

Exam Year: 2019

Solution:

Potential Energy (PE) = 1/2 * k * x^2 = 1/2 * 200 N/m * (0.1 m)^2 = 1 J

A spring is compressed by 0.1 m and has a spring constant of 200 N/m. What is the potential energy stored in the spring? (2019)

A spring is compressed by 0.1 m and has a spring constant of 200 N/m. What is the potential energy stored in the spring? (2019)

Step 1: Identify the formula for potential energy stored in a spring, which is PE = 1/2 * k * x^2.
Step 2: Identify the values needed for the formula: the spring constant (k) is 200 N/m and the compression distance (x) is 0.1 m.
Step 3: Substitute the values into the formula: PE = 1/2 * 200 N/m * (0.1 m)^2.
Step 4: Calculate (0.1 m)^2, which equals 0.01 m^2.
Step 5: Multiply 200 N/m by 0.01 m^2, which equals 2 N*m (or 2 J).
Step 6: Finally, multiply by 1/2: 1/2 * 2 J = 1 J.

Potential Energy in Springs – The potential energy stored in a compressed or stretched spring is calculated using the formula PE = 1/2 * k * x^2, where k is the spring constant and x is the displacement from the equilibrium position.