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What is the angular momentum of a particle of mass 2 kg moving in a circle of ra

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Question: What is the angular momentum of a particle of mass 2 kg moving in a circle of radius 3 m with a speed of 4 m/s? (2021)

Options:

24 kg·m²/s
12 kg·m²/s
6 kg·m²/s
8 kg·m²/s

Correct Answer: 24 kg·m²/s

Exam Year: 2021

Solution:

Angular momentum L = mvr, where v is the tangential speed. L = 2 kg * 4 m/s * 3 m = 24 kg·m²/s.

What is the angular momentum of a particle of mass 2 kg moving in a circle of ra

Practice Questions

Q1

What is the angular momentum of a particle of mass 2 kg moving in a circle of radius 3 m with a speed of 4 m/s? (2021)

24 kg·m²/s
12 kg·m²/s
6 kg·m²/s
8 kg·m²/s

Questions & Step-by-Step Solutions

What is the angular momentum of a particle of mass 2 kg moving in a circle of radius 3 m with a speed of 4 m/s? (2021)

Step 1: Identify the mass of the particle. In this case, the mass (m) is 2 kg.
Step 2: Identify the radius of the circle. Here, the radius (r) is 3 m.
Step 3: Identify the speed of the particle. The speed (v) is 4 m/s.
Step 4: Use the formula for angular momentum, which is L = mvr.
Step 5: Substitute the values into the formula: L = 2 kg * 4 m/s * 3 m.
Step 6: Calculate the result: L = 2 * 4 * 3 = 24 kg·m²/s.

Angular Momentum – Angular momentum is a measure of the rotational motion of an object, calculated as the product of mass, tangential speed, and radius from the axis of rotation.
Tangential Speed – Tangential speed is the linear speed of an object moving along a circular path, which is constant for uniform circular motion.
Units of Measurement – Understanding the units involved in the calculation, such as kg·m²/s for angular momentum.

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