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If a 5Ω resistor is connected to a 15V battery, what is the power dissipated by
If a 5Ω resistor is connected to a 15V battery, what is the power dissipated by the resistor? (2023)
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If a 5Ω resistor is connected to a 15V battery, what is the power dissipated by the resistor? (2023)
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Power (P) can be calculated using P = V^2 / R. Here, P = 15V^2 / 5Ω = 45W.
Questions & Step-by-step Solutions
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Q
Q: If a 5Ω resistor is connected to a 15V battery, what is the power dissipated by the resistor? (2023)
Solution:
Power (P) can be calculated using P = V^2 / R. Here, P = 15V^2 / 5Ω = 45W.
Steps: 6
Show Steps
Step 1: Identify the values given in the problem. We have a resistor of 5Ω and a battery of 15V.
Step 2: Recall the formula for power (P) in terms of voltage (V) and resistance (R). The formula is P = V^2 / R.
Step 3: Substitute the values into the formula. Here, V = 15V and R = 5Ω.
Step 4: Calculate V^2. This means 15V * 15V = 225V^2.
Step 5: Now divide 225V^2 by 5Ω. So, 225V^2 / 5Ω = 45W.
Step 6: The power dissipated by the resistor is 45W.
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