What is the force between two charges of +2μC and -3μC separated by 0.5m? (2022)

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Question: What is the force between two charges of +2μC and -3μC separated by 0.5m? (2022)

Options:

Correct Answer: 0.24 N

Exam Year: 2022

Solution:

Using Coulomb\'s law, F = k * |q1 * q2| / r^2 = (9 × 10^9) * (2 × 10^-6) * (3 × 10^-6) / (0.5)^2 = 0.24 N.

What is the force between two charges of +2μC and -3μC separated by 0.5m? (2022)

What is the force between two charges of +2μC and -3μC separated by 0.5m? (2022)

Step 1: Identify the charges. We have charge q1 = +2μC and charge q2 = -3μC.
Step 2: Convert the charges from microcoulombs (μC) to coulombs (C). +2μC = 2 × 10^-6 C and -3μC = -3 × 10^-6 C.
Step 3: Identify the distance between the charges. The distance r = 0.5m.
Step 4: Use Coulomb's law formula: F = k * |q1 * q2| / r^2, where k = 9 × 10^9 N m²/C².
Step 5: Calculate the product of the charges: |q1 * q2| = |(2 × 10^-6) * (-3 × 10^-6)| = 6 × 10^-12 C².
Step 6: Calculate r squared: r^2 = (0.5)^2 = 0.25 m².
Step 7: Substitute the values into the formula: F = (9 × 10^9) * (6 × 10^-12) / (0.25).
Step 8: Calculate the force: F = (9 × 10^9 * 6 × 10^-12) / 0.25 = 0.24 N.

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