A 10 kg object is at rest. A force of 30 N is applied to it. What will be its ve

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Question: A 10 kg object is at rest. A force of 30 N is applied to it. What will be its velocity after 3 seconds? (2023)

Options:

Correct Answer: 6 m/s

Exam Year: 2023

Solution:

First, find acceleration: a = F/m = 30 N / 10 kg = 3 m/s². Then, using v = u + at, v = 0 + 3 m/s² × 3 s = 9 m/s.

A 10 kg object is at rest. A force of 30 N is applied to it. What will be its velocity after 3 seconds? (2023)

A 10 kg object is at rest. A force of 30 N is applied to it. What will be its velocity after 3 seconds? (2023)

Step 1: Identify the mass of the object, which is 10 kg.
Step 2: Identify the force applied to the object, which is 30 N.
Step 3: Use the formula for acceleration, which is a = F/m.
Step 4: Substitute the values into the formula: a = 30 N / 10 kg.
Step 5: Calculate the acceleration: a = 3 m/s².
Step 6: Identify the initial velocity (u) of the object, which is 0 m/s since it is at rest.
Step 7: Use the formula for final velocity, which is v = u + at.
Step 8: Substitute the values into the formula: v = 0 + (3 m/s² × 3 s).
Step 9: Calculate the final velocity: v = 9 m/s.

Newton's Second Law of Motion – This law states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.
Kinematic Equations – These equations relate the variables of motion (initial velocity, final velocity, acceleration, time, and displacement) for uniformly accelerated motion.