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In a circuit with a 9V battery and two resistors of 3Ω and 6Ω in series, what is

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Question: In a circuit with a 9V battery and two resistors of 3Ω and 6Ω in series, what is the current flowing through the circuit? (2022)

Options:

  1. 1A
  2. 2A
  3. 3A
  4. 4A

Correct Answer: 2A

Exam Year: 2022

Solution: 

Total resistance R = 3Ω + 6Ω = 9Ω. Current I = V/R = 9V/9Ω = 1A.

In a circuit with a 9V battery and two resistors of 3Ω and 6Ω in series, what is

Practice Questions

Q1
In a circuit with a 9V battery and two resistors of 3Ω and 6Ω in series, what is the current flowing through the circuit? (2022)
  1. 1A
  2. 2A
  3. 3A
  4. 4A

Questions & Step-by-Step Solutions

In a circuit with a 9V battery and two resistors of 3Ω and 6Ω in series, what is the current flowing through the circuit? (2022)
  • Step 1: Identify the voltage of the battery, which is 9V.
  • Step 2: Identify the resistors in the circuit, which are 3Ω and 6Ω.
  • Step 3: Calculate the total resistance by adding the two resistors together: 3Ω + 6Ω = 9Ω.
  • Step 4: Use Ohm's Law to find the current. Ohm's Law states that Current (I) = Voltage (V) / Resistance (R).
  • Step 5: Substitute the values into the formula: I = 9V / 9Ω.
  • Step 6: Calculate the current: I = 1A.
  • Ohm's Law – The relationship between voltage (V), current (I), and resistance (R) in an electrical circuit, expressed as V = I * R.
  • Series Circuits – In a series circuit, the total resistance is the sum of individual resistances, and the same current flows through all components.
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