What is the voltage drop across a 3Ω resistor carrying a current of 4A? (2019)

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Question: What is the voltage drop across a 3Ω resistor carrying a current of 4A? (2019)

Options:

Correct Answer: 12V

Exam Year: 2019

Solution:

Using Ohm\'s law, V = I * R = 4A * 3Ω = 12V.

What is the voltage drop across a 3Ω resistor carrying a current of 4A? (2019)

What is the voltage drop across a 3Ω resistor carrying a current of 4A? (2019)

Step 1: Identify the values given in the problem. We have a resistor with a resistance of 3 ohms (Ω) and a current of 4 amperes (A).
Step 2: Recall Ohm's law, which states that voltage (V) is equal to current (I) multiplied by resistance (R). The formula is V = I * R.
Step 3: Substitute the values into the formula. Here, I = 4A and R = 3Ω.
Step 4: Calculate the voltage drop by multiplying the current by the resistance: V = 4A * 3Ω.
Step 5: Perform the multiplication: 4 * 3 = 12.
Step 6: Conclude that the voltage drop across the resistor is 12 volts (V).

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