If the vapor pressure of pure solvent is 100 mmHg, and the vapor pressure of the
Practice Questions
Q1
If the vapor pressure of pure solvent is 100 mmHg, and the vapor pressure of the solution is 80 mmHg, what is the relative lowering of vapor pressure? (2022)
0.2
0.1
0.5
0.3
Questions & Step-by-Step Solutions
If the vapor pressure of pure solvent is 100 mmHg, and the vapor pressure of the solution is 80 mmHg, what is the relative lowering of vapor pressure? (2022)
Step 1: Identify the vapor pressure of the pure solvent, which is given as 100 mmHg.
Step 2: Identify the vapor pressure of the solution, which is given as 80 mmHg.
Step 3: Calculate the difference between the vapor pressure of the pure solvent and the vapor pressure of the solution. This is done by subtracting the vapor pressure of the solution from the vapor pressure of the pure solvent: 100 mmHg - 80 mmHg = 20 mmHg.
Step 4: Now, to find the relative lowering of vapor pressure, use the formula: (P° - P) / P°, where P° is the vapor pressure of the pure solvent and P is the vapor pressure of the solution.
Step 5: Substitute the values into the formula: (100 mmHg - 80 mmHg) / 100 mmHg = 20 mmHg / 100 mmHg.
Step 6: Simplify the fraction: 20 / 100 = 0.2.
Vapor Pressure – The pressure exerted by a vapor in equilibrium with its liquid or solid phase.
Relative Lowering of Vapor Pressure – The decrease in vapor pressure of a solvent when a solute is added, expressed as a fraction of the original vapor pressure.
Raoult's Law – A principle stating that the vapor pressure of a solvent in a solution is directly proportional to the mole fraction of the solvent.
