Question: What is the total mechanical energy of a simple harmonic oscillator with a mass of 1 kg, amplitude of 0.1 m, and spring constant of 100 N/m? (2022)
Options:
Correct Answer: 1 J
Exam Year: 2022
Solution:
The total mechanical energy E is given by E = (1/2)kA². Therefore, E = (1/2)(100)(0.1)² = 0.5 J.