What is the latent heat of vaporization if 500 g of water at 100°C is converted

What is the latent heat of vaporization if 500 g of water at 100°C is converted to steam at the same temperature, absorbing 2260 kJ of heat? (2023)

What is the latent heat of vaporization if 500 g of water at 100°C is converted to steam at the same temperature, absorbing 2260 kJ of heat? (2023)

Step 1: Understand the problem. We need to find the latent heat of vaporization (L) of water when it is converted to steam.
Step 2: Identify the given values. We have 500 grams of water and it absorbs 2260 kJ of heat.
Step 3: Convert the heat absorbed from kJ to J. Since 1 kJ = 1000 J, we have 2260 kJ = 2260000 J.
Step 4: Use the formula for latent heat of vaporization: L = Q / m, where Q is the heat absorbed and m is the mass of the water.
Step 5: Substitute the values into the formula. L = 2260000 J / 500 g.
Step 6: Calculate the result. L = 4520 J/g.
Step 7: Convert the result to kJ/g if needed. Since 1 kJ = 1000 J, L = 4.52 kJ/g.

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