For which value of k does the equation x² - kx + 9 = 0 have no real roots? (2021

Practice Questions

Q1
For which value of k does the equation x² - kx + 9 = 0 have no real roots? (2021)
  1. 6
  2. 8
  3. 4
  4. 10

Questions & Step-by-Step Solutions

For which value of k does the equation x² - kx + 9 = 0 have no real roots? (2021)
  • Step 1: Identify the equation given, which is x² - kx + 9 = 0.
  • Step 2: Recognize that to find the roots of a quadratic equation, we use the discriminant formula, which is D = b² - 4ac.
  • Step 3: In our equation, a = 1, b = -k, and c = 9.
  • Step 4: Substitute the values into the discriminant formula: D = (-k)² - 4*1*9.
  • Step 5: Simplify the expression: D = k² - 36.
  • Step 6: For the equation to have no real roots, the discriminant must be less than zero: k² - 36 < 0.
  • Step 7: Rearrange the inequality: k² < 36.
  • Step 8: Take the square root of both sides: |k| < 6.
  • Step 9: This means k must be between -6 and 6, so k > 6 or k < -6.
  • Discriminant – The discriminant of a quadratic equation determines the nature of its roots. If the discriminant is less than zero, the equation has no real roots.
  • Quadratic Equation – A quadratic equation is in the form ax² + bx + c = 0, where a, b, and c are constants.
  • Inequalities – Understanding how to manipulate inequalities is crucial for determining the range of values for k.
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