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If a capacitor is charged to a voltage of 5 V and then disconnected from the bat

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Question: If a capacitor is charged to a voltage of 5 V and then disconnected from the battery, what happens to the charge on the capacitor if the voltage is increased to 10 V? (2023)

Options:

  1. Charge increases
  2. Charge decreases
  3. Charge remains the same
  4. Charge becomes zero

Correct Answer: Charge increases

Exam Year: 2023

Solution:

When the voltage is increased to 10 V, the charge on the capacitor increases because charge (Q) is directly proportional to voltage (V) for a given capacitance.

If a capacitor is charged to a voltage of 5 V and then disconnected from the bat

Practice Questions

Q1
If a capacitor is charged to a voltage of 5 V and then disconnected from the battery, what happens to the charge on the capacitor if the voltage is increased to 10 V? (2023)
  1. Charge increases
  2. Charge decreases
  3. Charge remains the same
  4. Charge becomes zero

Questions & Step-by-Step Solutions

If a capacitor is charged to a voltage of 5 V and then disconnected from the battery, what happens to the charge on the capacitor if the voltage is increased to 10 V? (2023)
  • Step 1: Understand that a capacitor stores electrical charge.
  • Step 2: Know that the charge (Q) on a capacitor is related to the voltage (V) and capacitance (C) by the formula Q = C * V.
  • Step 3: When the capacitor is charged to 5 V, it holds a certain amount of charge based on that voltage.
  • Step 4: Disconnecting the capacitor from the battery means it cannot gain or lose charge from the battery.
  • Step 5: If the voltage is increased to 10 V, this means we are considering a new scenario where the capacitor is now at a higher voltage.
  • Step 6: Since charge is directly proportional to voltage, increasing the voltage to 10 V will increase the charge on the capacitor.
  • Step 7: Therefore, the charge on the capacitor increases when the voltage is increased to 10 V.
  • Capacitance and Charge Relationship – The relationship between charge (Q), voltage (V), and capacitance (C) is given by the formula Q = C * V, indicating that charge is directly proportional to voltage for a constant capacitance.
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