What is the vapor pressure of a solution containing 1 mole of solute in 10 moles

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Question: What is the vapor pressure of a solution containing 1 mole of solute in 10 moles of solvent, assuming ideal behavior? (2019)

Options:

Correct Answer: 0.9 P0

Exam Year: 2019

Solution:

Using Raoult\'s law, the vapor pressure of the solution = (moles of solvent / total moles) * P0 = (10 / 11) * P0 ≈ 0.909 P0.

What is the vapor pressure of a solution containing 1 mole of solute in 10 moles of solvent, assuming ideal behavior? (2019)

What is the vapor pressure of a solution containing 1 mole of solute in 10 moles of solvent, assuming ideal behavior? (2019)

Step 1: Identify the number of moles of solute and solvent. Here, we have 1 mole of solute and 10 moles of solvent.
Step 2: Calculate the total number of moles in the solution. Total moles = moles of solute + moles of solvent = 1 + 10 = 11 moles.
Step 3: Use Raoult's law to find the vapor pressure of the solution. Raoult's law states that the vapor pressure of the solution is equal to the mole fraction of the solvent multiplied by the vapor pressure of the pure solvent (P0).
Step 4: Calculate the mole fraction of the solvent. Mole fraction of solvent = moles of solvent / total moles = 10 / 11.
Step 5: Multiply the mole fraction of the solvent by the vapor pressure of the pure solvent (P0) to find the vapor pressure of the solution. Vapor pressure of the solution = (10 / 11) * P0.
Step 6: Simplify the expression. This gives approximately 0.909 P0.

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