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For the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g), if the volume of the container is de

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Question: For the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g), if the volume of the container is decreased, what will happen to the equilibrium? (2021)

Options:

  1. Shift to the right
  2. Shift to the left
  3. No change
  4. Depends on the temperature

Correct Answer: Shift to the right

Exam Year: 2021

Solution: 

Decreasing the volume increases the pressure, and the equilibrium will shift towards the side with fewer moles of gas, which is the right side (2 moles of SO3).

For the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g), if the volume of the container is de

Practice Questions

Q1
For the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g), if the volume of the container is decreased, what will happen to the equilibrium? (2021)
  1. Shift to the right
  2. Shift to the left
  3. No change
  4. Depends on the temperature

Questions & Step-by-Step Solutions

For the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g), if the volume of the container is decreased, what will happen to the equilibrium? (2021)
  • Step 1: Understand that the reaction involves gases: 2SO2, O2, and SO3.
  • Step 2: Note that the left side of the reaction (2SO2 + O2) has 3 moles of gas (2 moles of SO2 + 1 mole of O2).
  • Step 3: The right side of the reaction (2SO3) has 2 moles of gas.
  • Step 4: When the volume of the container is decreased, the pressure inside the container increases.
  • Step 5: According to Le Chatelier's principle, the equilibrium will shift to reduce the pressure.
  • Step 6: The equilibrium will shift towards the side with fewer moles of gas to decrease the pressure.
  • Step 7: Since the right side has fewer moles (2 moles of SO3), the equilibrium will shift to the right.
  • Le Chatelier's Principle – This principle states that if a dynamic equilibrium is disturbed by changing the conditions, the position of equilibrium shifts to counteract the change.
  • Gas Laws – Understanding how changes in volume and pressure affect gas reactions and equilibrium.
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