A 1500 kg car accelerates from rest to a speed of 25 m/s. What is the work done

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Question: A 1500 kg car accelerates from rest to a speed of 25 m/s. What is the work done on the car?

Options:

Correct Answer: 468,750 J

Solution:

Work done = Change in Kinetic Energy = 0.5 * m * v² = 0.5 * 1500 kg * (25 m/s)² = 468,750 J.

A 1500 kg car accelerates from rest to a speed of 25 m/s. What is the work done on the car?

A 1500 kg car accelerates from rest to a speed of 25 m/s. What is the work done on the car?

Correct Answer: 468750 J

Step 1: Identify the mass of the car, which is 1500 kg.
Step 2: Identify the final speed of the car, which is 25 m/s.
Step 3: Understand that the car starts from rest, so the initial speed is 0 m/s.
Step 4: Recall the formula for kinetic energy: KE = 0.5 * m * v².
Step 5: Substitute the mass (1500 kg) and the final speed (25 m/s) into the formula.
Step 6: Calculate the square of the speed: (25 m/s)² = 625 m²/s².
Step 7: Multiply the mass by the square of the speed: 1500 kg * 625 m²/s² = 937500 kg*m²/s².
Step 8: Multiply by 0.5: 0.5 * 937500 = 468750 J.
Step 9: Conclude that the work done on the car is 468750 Joules.

Kinetic Energy – The energy an object possesses due to its motion, calculated as KE = 0.5 * m * v².
Work-Energy Principle – The principle stating that the work done on an object is equal to the change in its kinetic energy.
Units of Work – Work is measured in joules (J), where 1 J = 1 kg·m²/s².