A block of mass 2 kg is lifted to a height of 5 m. What is the work done against
Practice Questions
Q1
A block of mass 2 kg is lifted to a height of 5 m. What is the work done against gravity? (g = 9.8 m/s²)
98 J
196 J
49 J
20 J
Questions & Step-by-Step Solutions
A block of mass 2 kg is lifted to a height of 5 m. What is the work done against gravity? (g = 9.8 m/s²)
Correct Answer: 98 J
Step 1: Identify the mass of the block. The mass is given as 2 kg.
Step 2: Identify the height to which the block is lifted. The height is given as 5 m.
Step 3: Identify the acceleration due to gravity. It is given as 9.8 m/s².
Step 4: Use the formula for work done against gravity, which is Work = mass * gravity * height.
Step 5: Substitute the values into the formula: Work = 2 kg * 9.8 m/s² * 5 m.
Step 6: Calculate the result: 2 * 9.8 * 5 = 98 J.
Step 7: Conclude that the work done against gravity is 98 Joules.
Work Done Against Gravity – The work done against gravity is calculated using the formula W = mgh, where W is work, m is mass, g is acceleration due to gravity, and h is height.
