What is the force on a charge moving in a magnetic field given by F = qvB sin(θ)
Practice Questions
Q1
What is the force on a charge moving in a magnetic field given by F = qvB sin(θ)? (2022)
It is always zero
It depends on the angle θ
It is constant
It is maximum when θ = 90°
Questions & Step-by-Step Solutions
What is the force on a charge moving in a magnetic field given by F = qvB sin(θ)? (2022)
Step 1: Identify the variables in the formula F = qvB sin(θ). Here, F is the force, q is the charge, v is the velocity, B is the magnetic field strength, and θ is the angle between the velocity and the magnetic field.
Step 2: Understand that the force depends on the angle θ. The sine function (sin) tells us how much of the velocity is effective in creating force in the magnetic field.
Step 3: Recognize that sin(θ) reaches its maximum value of 1 when θ is 90 degrees. This means the charge is moving perpendicular to the magnetic field.
Step 4: Conclude that the force on the charge is greatest when it moves at a right angle to the magnetic field, which is when θ = 90°.
