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What is the force on a charge moving in a magnetic field given by F = qvB sin(θ)

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Question: What is the force on a charge moving in a magnetic field given by F = qvB sin(θ)? (2022)

Options:

  1. It is always zero
  2. It depends on the angle θ
  3. It is constant
  4. It is maximum when θ = 90°

Correct Answer: It is maximum when θ = 90°

Exam Year: 2022

Solution: 

The force on a charge moving in a magnetic field is maximum when the angle θ between the velocity vector and the magnetic field is 90°, as sin(90°) = 1.

What is the force on a charge moving in a magnetic field given by F = qvB sin(θ)

Practice Questions

Q1
What is the force on a charge moving in a magnetic field given by F = qvB sin(θ)? (2022)
  1. It is always zero
  2. It depends on the angle θ
  3. It is constant
  4. It is maximum when θ = 90°

Questions & Step-by-Step Solutions

What is the force on a charge moving in a magnetic field given by F = qvB sin(θ)? (2022)
  • Step 1: Identify the variables in the formula F = qvB sin(θ). Here, F is the force, q is the charge, v is the velocity, B is the magnetic field strength, and θ is the angle between the velocity and the magnetic field.
  • Step 2: Understand that the force depends on the angle θ. The sine function (sin) tells us how much of the velocity is effective in creating force in the magnetic field.
  • Step 3: Recognize that sin(θ) reaches its maximum value of 1 when θ is 90 degrees. This means the charge is moving perpendicular to the magnetic field.
  • Step 4: Conclude that the force on the charge is greatest when it moves at a right angle to the magnetic field, which is when θ = 90°.
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