What is the total resistance of two 4Ω resistors connected in series? (2020)

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Question: What is the total resistance of two 4Ω resistors connected in series? (2020)

Options:

Correct Answer: 8Ω

Exam Year: 2020

Solution:

In series, R_eq = R1 + R2 = 4Ω + 4Ω = 8Ω.

What is the total resistance of two 4Ω resistors connected in series? (2020)

What is the total resistance of two 4Ω resistors connected in series? (2020)

Step 1: Identify the resistors. We have two resistors, each with a resistance of 4Ω.
Step 2: Understand that when resistors are connected in series, their total resistance is the sum of their individual resistances.
Step 3: Write down the formula for total resistance in series: R_eq = R1 + R2.
Step 4: Substitute the values of the resistors into the formula: R_eq = 4Ω + 4Ω.
Step 5: Perform the addition: 4Ω + 4Ω = 8Ω.
Step 6: Conclude that the total resistance of the two 4Ω resistors connected in series is 8Ω.

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