For the matrix E = [[1, 2, 3], [0, 1, 4], [5, 6, 0]], find the determinant. (202

₹0.0

Question: For the matrix E = [[1, 2, 3], [0, 1, 4], [5, 6, 0]], find the determinant. (2023)

Options:

Correct Answer: -24

Exam Year: 2023

Solution:

Determinant of E = 1(1*0 - 4*6) - 2(0*0 - 4*5) + 3(0*6 - 1*5) = 1(0 - 24) - 2(0 - 20) + 3(0 - 5) = -24 + 40 - 15 = 1.

For the matrix E = [[1, 2, 3], [0, 1, 4], [5, 6, 0]], find the determinant. (2023)

For the matrix E = [[1, 2, 3], [0, 1, 4], [5, 6, 0]], find the determinant. (2023)

Step 1: Identify the matrix E, which is E = [[1, 2, 3], [0, 1, 4], [5, 6, 0]].
Step 2: Write down the formula for the determinant of a 3x3 matrix: det(E) = a(ei - fh) - b(di - fg) + c(dh - eg), where the matrix is [[a, b, c], [d, e, f], [g, h, i]].
Step 3: Assign values from the matrix to the variables: a = 1, b = 2, c = 3, d = 0, e = 1, f = 4, g = 5, h = 6, i = 0.
Step 4: Calculate the first part: ei - fh = (1*0) - (4*6) = 0 - 24 = -24.
Step 5: Calculate the second part: di - fg = (0*0) - (4*5) = 0 - 20 = -20.
Step 6: Calculate the third part: dh - eg = (0*6) - (1*5) = 0 - 5 = -5.
Step 7: Substitute these values back into the determinant formula: det(E) = 1(-24) - 2(-20) + 3(-5).
Step 8: Simplify the expression: det(E) = -24 + 40 - 15.
Step 9: Calculate the final result: -24 + 40 = 16, and then 16 - 15 = 1.
Step 10: Conclude that the determinant of matrix E is 1.

Determinant Calculation – The question tests the ability to compute the determinant of a 3x3 matrix using the cofactor expansion method.
Matrix Operations – Understanding how to perform basic matrix operations and apply the determinant formula correctly.