A 1 kg object is dropped from a height. What is its velocity just before it hits

₹0.0

Question: A 1 kg object is dropped from a height. What is its velocity just before it hits the ground (neglect air resistance)? (2020)

Options:

Correct Answer: 20 m/s

Exam Year: 2020

Solution:

Using v² = u² + 2gh, v = √(0 + 2 × 9.8 m/s² × h). For h = 20 m, v = √(392) = 20 m/s.

A 1 kg object is dropped from a height. What is its velocity just before it hits the ground (neglect air resistance)? (2020)

A 1 kg object is dropped from a height. What is its velocity just before it hits the ground (neglect air resistance)? (2020)

Step 1: Identify the initial velocity (u) of the object. Since it is dropped, u = 0 m/s.
Step 2: Identify the acceleration due to gravity (g). This is approximately 9.8 m/s².
Step 3: Identify the height (h) from which the object is dropped. In this case, h = 20 m.
Step 4: Use the formula v² = u² + 2gh to find the final velocity (v) just before hitting the ground.
Step 5: Substitute the values into the formula: v² = 0 + 2 × 9.8 m/s² × 20 m.
Step 6: Calculate the right side: 2 × 9.8 × 20 = 392.
Step 7: Take the square root of 392 to find v: v = √392.
Step 8: Calculate √392, which is approximately 20 m/s.

Kinematics – The question tests the understanding of kinematic equations, specifically the relationship between initial velocity, final velocity, acceleration due to gravity, and displacement.
Free Fall – The scenario involves an object in free fall, allowing the application of gravitational acceleration without air resistance.