A charge of +10 µC is placed in an electric field of strength 2000 N/C. What is

Practice Questions

Q1
A charge of +10 µC is placed in an electric field of strength 2000 N/C. What is the force acting on the charge? (2023)
  1. 20 N
  2. 200 N
  3. 2 N
  4. 0.2 N

Questions & Step-by-Step Solutions

A charge of +10 µC is placed in an electric field of strength 2000 N/C. What is the force acting on the charge? (2023)
  • Step 1: Identify the charge value. The charge is +10 µC (microcoulombs). Convert this to coulombs: 10 µC = 10 × 10^-6 C.
  • Step 2: Identify the electric field strength. The electric field strength is given as 2000 N/C.
  • Step 3: Use the formula for force in an electric field, which is F = qE, where F is the force, q is the charge, and E is the electric field strength.
  • Step 4: Substitute the values into the formula: F = (10 × 10^-6 C) * (2000 N/C).
  • Step 5: Calculate the force: F = 10 × 2000 × 10^-6 N = 20000 × 10^-6 N = 0.02 N.
  • Step 6: Convert the force to a more understandable unit if needed: 0.02 N is the same as 20 mN (millinewtons).
  • Electric Force Calculation – The question tests the ability to calculate the force acting on a charge in an electric field using the formula F = qE, where F is the force, q is the charge, and E is the electric field strength.
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