What is the area of a triangle with vertices at A(0, 0, 0), B(1, 0, 0), and C(0,

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Question: What is the area of a triangle with vertices at A(0, 0, 0), B(1, 0, 0), and C(0, 1, 0)? (2022)

Options:

Correct Answer: 0.5

Exam Year: 2022

Solution:

Area = 0.5 * base * height = 0.5 * 1 * 1 = 0.5 square units.

What is the area of a triangle with vertices at A(0, 0, 0), B(1, 0, 0), and C(0, 1, 0)? (2022)

What is the area of a triangle with vertices at A(0, 0, 0), B(1, 0, 0), and C(0, 1, 0)? (2022)

Step 1: Identify the vertices of the triangle. The vertices are A(0, 0, 0), B(1, 0, 0), and C(0, 1, 0).
Step 2: Determine the base of the triangle. The base can be the distance between points A and B, which is 1 unit.
Step 3: Determine the height of the triangle. The height is the distance from point C to the line AB, which is also 1 unit.
Step 4: Use the formula for the area of a triangle: Area = 0.5 * base * height.
Step 5: Substitute the values into the formula: Area = 0.5 * 1 * 1.
Step 6: Calculate the area: Area = 0.5 square units.

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