What type of reaction occurs when 2-bromopropane is treated with aqueous KOH? (2

Practice Questions

Q1
What type of reaction occurs when 2-bromopropane is treated with aqueous KOH? (2023)
  1. Elimination
  2. Substitution
  3. Addition
  4. Redox

Questions & Step-by-Step Solutions

What type of reaction occurs when 2-bromopropane is treated with aqueous KOH? (2023)
  • Step 1: Identify the reactant, which is 2-bromopropane. It is a molecule that contains a bromine atom attached to a propane chain.
  • Step 2: Identify the reagent, which is aqueous KOH. This means potassium hydroxide is dissolved in water.
  • Step 3: Understand that KOH can act as a base in this reaction.
  • Step 4: Recognize that when a base is present, it can remove a hydrogen atom from the carbon chain of 2-bromopropane.
  • Step 5: When the hydrogen is removed, the bromine atom leaves as a bromide ion, resulting in the formation of a double bond between the carbon atoms.
  • Step 6: The product of this reaction is propene, which is an alkene with a double bond.
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