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A 10 kg object is dropped from a height of 20 m. What is its potential energy at
A 10 kg object is dropped from a height of 20 m. What is its potential energy at the top? (g = 9.8 m/s²) (1960)
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A 10 kg object is dropped from a height of 20 m. What is its potential energy at the top? (g = 9.8 m/s²) (1960)
196 J
98 J
294 J
490 J
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Potential Energy (PE) = mgh = 10 kg × 9.8 m/s² × 20 m = 1960 J.
Questions & Step-by-step Solutions
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Q
Q: A 10 kg object is dropped from a height of 20 m. What is its potential energy at the top? (g = 9.8 m/s²) (1960)
Solution:
Potential Energy (PE) = mgh = 10 kg × 9.8 m/s² × 20 m = 1960 J.
Steps: 7
Show Steps
Step 1: Identify the mass of the object. In this case, the mass (m) is 10 kg.
Step 2: Identify the height from which the object is dropped. The height (h) is 20 m.
Step 3: Identify the acceleration due to gravity. The value of g is 9.8 m/s².
Step 4: Use the formula for potential energy (PE), which is PE = mgh.
Step 5: Substitute the values into the formula: PE = 10 kg × 9.8 m/s² × 20 m.
Step 6: Calculate the result: 10 × 9.8 × 20 = 1960 J.
Step 7: Conclude that the potential energy at the top is 1960 Joules.
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