If one root of the equation x² - 7x + p = 0 is 3, what is the value of p? (2020)

Practice Questions

Q1
If one root of the equation x² - 7x + p = 0 is 3, what is the value of p? (2020)
  1. 6
  2. 9
  3. 12
  4. 15

Questions & Step-by-Step Solutions

If one root of the equation x² - 7x + p = 0 is 3, what is the value of p? (2020)
  • Step 1: Start with the equation x² - 7x + p = 0.
  • Step 2: We know that one root of the equation is 3. This means that if we substitute x with 3, the equation should equal 0.
  • Step 3: Substitute x = 3 into the equation: 3² - 7*3 + p = 0.
  • Step 4: Calculate 3², which is 9.
  • Step 5: Calculate 7*3, which is 21.
  • Step 6: Now, rewrite the equation with these values: 9 - 21 + p = 0.
  • Step 7: Simplify the left side: 9 - 21 equals -12, so we have -12 + p = 0.
  • Step 8: To find p, add 12 to both sides of the equation: p = 12.
  • Step 9: Therefore, the value of p is 12.
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