A tuning fork vibrates at a frequency of 440 Hz. What is the time period of the
Practice Questions
Q1
A tuning fork vibrates at a frequency of 440 Hz. What is the time period of the tuning fork? (2020)
0.00227 s
0.0045 s
0.01 s
0.005 s
Questions & Step-by-Step Solutions
A tuning fork vibrates at a frequency of 440 Hz. What is the time period of the tuning fork? (2020)
Step 1: Understand that frequency (f) is the number of vibrations per second, measured in Hertz (Hz). In this case, the frequency is 440 Hz.
Step 2: Know that the time period (T) is the time taken for one complete vibration. It is the inverse of frequency.
Step 3: Use the formula for time period: T = 1 / f.
Step 4: Substitute the frequency into the formula: T = 1 / 440 Hz.
Step 5: Calculate the time period: T ≈ 0.00227 seconds.
Frequency and Time Period – The relationship between frequency and time period is given by the formula T = 1/f, where T is the time period and f is the frequency.
