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Evaluate: sin^(-1)(1) + cos^(-1)(0).
Evaluate: sin^(-1)(1) + cos^(-1)(0).
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Practice Questions
1 question
Q1
Evaluate: sin^(-1)(1) + cos^(-1)(0).
π/2
π
0
1
Show Solution
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sin^(-1)(1) = π/2 and cos^(-1)(0) = π/2. Therefore, π/2 + π/2 = π.
Questions & Step-by-step Solutions
1 item
Q
Q: Evaluate: sin^(-1)(1) + cos^(-1)(0).
Solution:
sin^(-1)(1) = π/2 and cos^(-1)(0) = π/2. Therefore, π/2 + π/2 = π.
Steps: 5
Show Steps
Step 1: Understand the notation sin^(-1)(1) and cos^(-1)(0). This means we are looking for the angles whose sine is 1 and whose cosine is 0.
Step 2: Find sin^(-1)(1). The sine of an angle is 1 at π/2 radians (90 degrees). So, sin^(-1)(1) = π/2.
Step 3: Find cos^(-1)(0). The cosine of an angle is 0 at π/2 radians (90 degrees). So, cos^(-1)(0) = π/2.
Step 4: Add the results from Step 2 and Step 3. We have π/2 + π/2.
Step 5: Calculate π/2 + π/2. This equals π (since π/2 + π/2 = 2π/2 = π).
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