Question: In a mixture of two liquids, if the first liquid is 60% pure and the second is 80% pure, what is the overall purity if they are mixed in equal volumes?
Options:
70%
75%
80%
85%
Correct Answer: 70%
Solution:
Overall purity = (60% + 80%) / 2 = 70%.
In a mixture of two liquids, if the first liquid is 60% pure and the second is 8
Practice Questions
Q1
In a mixture of two liquids, if the first liquid is 60% pure and the second is 80% pure, what is the overall purity if they are mixed in equal volumes?
70%
75%
80%
85%
Questions & Step-by-Step Solutions
In a mixture of two liquids, if the first liquid is 60% pure and the second is 80% pure, what is the overall purity if they are mixed in equal volumes?
Step 1: Identify the purity of the first liquid, which is 60%.
Step 2: Identify the purity of the second liquid, which is 80%.
Step 3: Since the liquids are mixed in equal volumes, we will average their purities.
Step 5: Divide the total by 2 to find the average: 140% / 2 = 70%.
Step 6: The overall purity of the mixture is 70%.
Mixture Purity Calculation – Understanding how to calculate the overall purity of a mixture based on the purities of individual components and their volumes.
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