Question: A mixture contains 40% alcohol and 60% water. If 5 liters of the mixture is taken out and replaced with 5 liters of pure alcohol, what will be the new percentage of alcohol in the mixture?
Options:
Correct Answer: 55%
Solution:
After removing 5 liters of the mixture, the remaining alcohol is 0.4 * (total volume - 5) + 5 liters of pure alcohol.